Figure shows a rod of length L which is uniformly charged with linear charge density λ kept on a smooth horizontal surface. Right end of rod is in contact with a vertical fixed wall. A block of mass m and charge q is projected with a velocity v from a point very far from rod in the line of rod. Find the distance of closest approach between the block & the left end A of the rod.
Text Solution
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r = 
Sol. Let the closest distance of approach be r
Consider an element of length 'dx' on rod at a distance x from end 'A' of rod.
Potential at point B due to the element = 
.
∴ Potential at B, due to the rod = 
= kλ λ n 
Now applying conservation of energy
0 + 
mv 2 = q 
+ 0
⇒ 
= 
⇒ r = 
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